Optimal. Leaf size=178 \[ \frac{d x^{m+1} \left (a+b \sec ^{-1}(c x)\right )}{m+1}+\frac{e x^{m+3} \left (a+b \sec ^{-1}(c x)\right )}{m+3}+\frac{b \sqrt{c^2 x^2-1} x^{m+2} \left (c^2 d (m+2) (m+3)+e (m+1)^2\right ) \, _2F_1\left (1,\frac{m+2}{2};\frac{m+3}{2};c^2 x^2\right )}{c (m+1)^2 (m+2) (m+3) \sqrt{c^2 x^2}}-\frac{b e \sqrt{c^2 x^2-1} x^{m+2}}{c \left (m^2+5 m+6\right ) \sqrt{c^2 x^2}} \]
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Rubi [A] time = 0.187007, antiderivative size = 204, normalized size of antiderivative = 1.15, number of steps used = 5, number of rules used = 6, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.286, Rules used = {14, 5238, 12, 459, 365, 364} \[ \frac{d (f x)^{m+1} \left (a+b \sec ^{-1}(c x)\right )}{f (m+1)}+\frac{e (f x)^{m+3} \left (a+b \sec ^{-1}(c x)\right )}{f^3 (m+3)}-\frac{b c x \sqrt{1-c^2 x^2} (f x)^{m+1} \left (\frac{e}{c^2 (m+2) (m+3)}+\frac{d}{(m+1)^2}\right ) \, _2F_1\left (\frac{1}{2},\frac{m+1}{2};\frac{m+3}{2};c^2 x^2\right )}{f \sqrt{c^2 x^2} \sqrt{c^2 x^2-1}}-\frac{b e x \sqrt{c^2 x^2-1} (f x)^{m+1}}{c f \left (m^2+5 m+6\right ) \sqrt{c^2 x^2}} \]
Warning: Unable to verify antiderivative.
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Rule 14
Rule 5238
Rule 12
Rule 459
Rule 365
Rule 364
Rubi steps
\begin{align*} \int (f x)^m \left (d+e x^2\right ) \left (a+b \sec ^{-1}(c x)\right ) \, dx &=\frac{d (f x)^{1+m} \left (a+b \sec ^{-1}(c x)\right )}{f (1+m)}+\frac{e (f x)^{3+m} \left (a+b \sec ^{-1}(c x)\right )}{f^3 (3+m)}-\frac{(b c x) \int \frac{(f x)^m \left (d (3+m)+e (1+m) x^2\right )}{(1+m) (3+m) \sqrt{-1+c^2 x^2}} \, dx}{\sqrt{c^2 x^2}}\\ &=\frac{d (f x)^{1+m} \left (a+b \sec ^{-1}(c x)\right )}{f (1+m)}+\frac{e (f x)^{3+m} \left (a+b \sec ^{-1}(c x)\right )}{f^3 (3+m)}-\frac{(b c x) \int \frac{(f x)^m \left (d (3+m)+e (1+m) x^2\right )}{\sqrt{-1+c^2 x^2}} \, dx}{\left (3+4 m+m^2\right ) \sqrt{c^2 x^2}}\\ &=-\frac{b e x (f x)^{1+m} \sqrt{-1+c^2 x^2}}{c f \left (6+5 m+m^2\right ) \sqrt{c^2 x^2}}+\frac{d (f x)^{1+m} \left (a+b \sec ^{-1}(c x)\right )}{f (1+m)}+\frac{e (f x)^{3+m} \left (a+b \sec ^{-1}(c x)\right )}{f^3 (3+m)}+\frac{\left (b c \left (-\frac{e (1+m)^2}{c^2 (2+m)}-d (3+m)\right ) x\right ) \int \frac{(f x)^m}{\sqrt{-1+c^2 x^2}} \, dx}{\left (3+4 m+m^2\right ) \sqrt{c^2 x^2}}\\ &=-\frac{b e x (f x)^{1+m} \sqrt{-1+c^2 x^2}}{c f \left (6+5 m+m^2\right ) \sqrt{c^2 x^2}}+\frac{d (f x)^{1+m} \left (a+b \sec ^{-1}(c x)\right )}{f (1+m)}+\frac{e (f x)^{3+m} \left (a+b \sec ^{-1}(c x)\right )}{f^3 (3+m)}+\frac{\left (b c \left (-\frac{e (1+m)^2}{c^2 (2+m)}-d (3+m)\right ) x \sqrt{1-c^2 x^2}\right ) \int \frac{(f x)^m}{\sqrt{1-c^2 x^2}} \, dx}{\left (3+4 m+m^2\right ) \sqrt{c^2 x^2} \sqrt{-1+c^2 x^2}}\\ &=-\frac{b e x (f x)^{1+m} \sqrt{-1+c^2 x^2}}{c f \left (6+5 m+m^2\right ) \sqrt{c^2 x^2}}+\frac{d (f x)^{1+m} \left (a+b \sec ^{-1}(c x)\right )}{f (1+m)}+\frac{e (f x)^{3+m} \left (a+b \sec ^{-1}(c x)\right )}{f^3 (3+m)}-\frac{b c \left (\frac{e (1+m)^2}{c^2 (2+m)}+d (3+m)\right ) x (f x)^{1+m} \sqrt{1-c^2 x^2} \, _2F_1\left (\frac{1}{2},\frac{1+m}{2};\frac{3+m}{2};c^2 x^2\right )}{f (1+m) \left (3+4 m+m^2\right ) \sqrt{c^2 x^2} \sqrt{-1+c^2 x^2}}\\ \end{align*}
Mathematica [F] time = 0.101336, size = 0, normalized size = 0. \[ \int (f x)^m \left (d+e x^2\right ) \left (a+b \sec ^{-1}(c x)\right ) \, dx \]
Verification is Not applicable to the result.
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Maple [F] time = 2.319, size = 0, normalized size = 0. \begin{align*} \int \left ( fx \right ) ^{m} \left ( e{x}^{2}+d \right ) \left ( a+b{\rm arcsec} \left (cx\right ) \right ) \, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (a e x^{2} + a d +{\left (b e x^{2} + b d\right )} \operatorname{arcsec}\left (c x\right )\right )} \left (f x\right )^{m}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (e x^{2} + d\right )}{\left (b \operatorname{arcsec}\left (c x\right ) + a\right )} \left (f x\right )^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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